integral of xcos(3x+1)

Lösung

\int x cos (3 x + 1) d x

\frac{1}{3} x sin (3 x + 1) + \frac{1}{9} cos (3 x + 1) + C

Schritte zur Lösung

\int x cos (3 x + 1) d x

Wende die partielle Integration an

= \frac{1}{3} x sin (3 x + 1) - \int \frac{1}{3} sin (3 x + 1) d x

\int \frac{1}{3} sin (3 x + 1) d x = - \frac{1}{9} cos (3 x + 1)

= \frac{1}{3} x sin (3 x + 1) - (- \frac{1}{9} cos (3 x + 1))

Vereinfache

= \frac{1}{3} x sin (3 x + 1) + \frac{1}{9} cos (3 x + 1)

Füge eine Konstante zur Lösung hinzu

= \frac{1}{3} x sin (3 x + 1) + \frac{1}{9} cos (3 x + 1) + C

\frac{d}{d x} (5 ln (6 - x^{2}))

\frac{d}{d x} (4 x d x)

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 9})

\frac{\partial}{\partial x} ((y - 2) tan (y))

d er i v a t i v e (2 x + 1)^{5}