derivative f(x)=-2x^2-20x-48

Lösung

ableitung von

f (x) = - 2 x^{2} - 20 x - 48

- 4 x - 20

Schritte zur Lösung

\frac{d}{d x} (- 2 x^{2} - 20 x - 48)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (20 x) - \frac{d}{d x} (48)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (20 x) = 20

\frac{d}{d x} (48) = 0

= - 4 x - 20 - 0

Vereinfache

= - 4 x - 20

\int x^{2} e^{2} x d x

\int_{- \infty}^{3} \frac{1}{x ^{2} + 9} d x

x \to 0 lim (3 - 4 x)

\frac{d y}{d t} + y = cos (t)

x \to 0 lim (\frac{x ∣ x ∣}{x})