y^{''}+4y=x^2

Lösung

y^{^{''}} + 4 y = x^{2}

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{x ^{2}}{4} - \frac{1}{8}

Schritte zur Lösung

y^{''} (x) + 4 y = x^{2}

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{x ^{2}}{4} - \frac{1}{8}

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{x ^{2}}{4} - \frac{1}{8}

\frac{d}{d x} (\frac{ln ( 3 x ^{2} - 6 x )}{4 x ^{3} - 2})

\frac{d}{d x} (4 sec (4 x))

n = 1 \sum \infty cos (\frac{1}{n})

\frac{d}{d x} (ln (\frac{1 + sin ( 4 x )}{cos ( 4 x )}))

\frac{d}{d x} (4 a x)