y^{''}-10y^'+25y=0,y(0)=1,y(1)=0

Lösung

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 1, y (1) = 0

y = e^{5 t} - e^{5 t} t

Schritte zur Lösung

y^{''} (t) - 10 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = e^{5 t} - e^{5 t} t

y = e^{5 t} - e^{5 t} t

d er i v a t i v e \frac{1}{7 x}

\frac{\partial}{\partial x} (sin (8 π t + 9 x))

\frac{d}{d x} (x - 3 y)

\int_{- 2}^{3} \frac{42}{x ^{4}} d x

\frac{d}{d x} (8 x - \frac{3}{x})