derivative of arccos(1-2x^2)

解答

\frac{d}{d x} (arccos (1 - 2 x^{2}))

\frac{2 2}{- 2 x ^{2} + 2}

求解步骤

\frac{d}{d x} (arccos (1 - 2 x^{2}))

使用连锁律:

- \frac{1}{1 - ( 1 - 2 x ^{2} ) ^{2}} \frac{d}{d x} (1 - 2 x^{2})

= - \frac{1}{1 - ( 1 - 2 x ^{2} ) ^{2}} \frac{d}{d x} (1 - 2 x^{2})

\frac{d}{d x} (1 - 2 x^{2}) = - 4 x

= - \frac{1}{1 - ( 1 - 2 x ^{2} ) ^{2}} (- 4 x)

化简

- \frac{1}{1 - ( 1 - 2 x ^{2} ) ^{2}} (- 4 x) : \frac{2 2}{- 2 x ^{2} + 2}

= \frac{2 2}{- 2 x ^{2} + 2}

a re a y = 6 - 6 x, y = 0, x = 0

\frac{\partial}{\partial x} (- x^{2} + 2 x y - y^{2})

\int csc^{4} (3 x) d x

\int \frac{x}{1 - x ^{2}} d x

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 6})