2x^2yy^'+2xy^2+1=0

Lösung

2 x^{2} y y^{^{'}} + 2 x y^{2} + 1 = 0

y = \frac{- x + c _{1}}{x}, y = - \frac{- x + c _{1}}{x}

Schritte zur Lösung

2 x^{2} y y^{'} (x) + 2 x y^{2} + 1 = 0

Solve Bernoulli ODE:

y = \frac{- x + c _{1}}{x}, y = - \frac{- x + c _{1}}{x}

y = \frac{- x + c _{1}}{x}, y = - \frac{- x + c _{1}}{x}

\frac{d}{d x} (3 ln (x + 1))

\frac{d}{d x} (35 x ln (13 x))

\frac{d}{d x} (6 x^{5} - 20 x^{4} + 20 x^{3} - 10 x + 4)

\int_{0}^{5} \frac{1}{x ^{\frac{18}{17}}} d x

x \to - \infty lim (1)