derivative of 6x^4-7x^3+2x+sqrt(2)

解

\frac{d}{d x} (6 x^{4} - 7 x^{3} + 2 x + 2)

24 x^{3} - 21 x^{2} + 2

解答ステップ

\frac{d}{d x} (6 x^{4} - 7 x^{3} + 2 x + 2)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{4}) - \frac{d}{d x} (7 x^{3}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (2)

\frac{d}{d x} (6 x^{4}) = 24 x^{3}

\frac{d}{d x} (7 x^{3}) = 21 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= 24 x^{3} - 21 x^{2} + 2 + 0

簡素化

= 24 x^{3} - 21 x^{2} + 2