What is the limit as s approaches-1 of 1/(s^2+2s+1) ?

The limit as s approaches-1 of 1/(s^2+2s+1) is infinity

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limit as s approaches-1 of 1/(s^2+2s+1)

s \to - 1 lim (\frac{1}{s ^{2} + 2 s + 1})

\infty

Solution steps

s \to - 1 lim (\frac{1}{s ^{2} + 2 s + 1})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

s \to - 1 - lim (\frac{1}{s ^{2} + 2 s + 1}) = \infty

s \to - 1 + lim (\frac{1}{s ^{2} + 2 s + 1}) = \infty

= \infty

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d er i v a t i v e y = x - 1

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(2 y^{2} + 3 x y - 2 y + 6 x) d x + x (x + 2 y - 1) d y = 0

\int \frac{( 4 x - 1 )}{3 3 x + 1} d x

What is the limit as s approaches-1 of 1/(s^2+2s+1) ?
The limit as s approaches-1 of 1/(s^2+2s+1) is infinity