integral of (3t^2-4t-4)

Lösung

\int (3 t^{2} - 4 t - 4) d t

t^{3} - 2 t^{2} - 4 t + C

Schritte zur Lösung

\int 3 t^{2} - 4 t - 4 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 t^{2} d t - \int 4 t d t - \int 4 d t

\int 3 t^{2} d t = t^{3}

\int 4 t d t = 2 t^{2}

\int 4 d t = 4 t

= t^{3} - 2 t^{2} - 4 t

Füge eine Konstante zur Lösung hinzu

= t^{3} - 2 t^{2} - 4 t + C

\int_{0}^{3} t e^{- t} d t

a re a y^{2} = 4 x, 4 x - 3 y = 4

\int_{1}^{5} \frac{x}{2 x - 1} d x

x \to 0 lim (cos (x) + sin (x))

\frac{d y}{d x} = \frac{( y ^{2} - 1 )}{x ^{2} - 1}, y (7) = 7