What is the derivative of ln(sqrt(x^2e^{x^{2+1)}}) ?

The derivative of ln(sqrt(x^2e^{x^{2+1)}}) is (3x^2|x|+2)/(2|x|)

What is the first derivative of ln(sqrt(x^2e^{x^{2+1)}}) ?

The first derivative of ln(sqrt(x^2e^{x^{2+1)}}) is (3x^2|x|+2)/(2|x|)

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\frac{d}{d x} (ln (x^{2} e^{x^{2 + 1}}))

\frac{3 x ^{2} ∣ x ∣ + 2}{2 ∣ x ∣}

Solution steps

\frac{d}{d x} (ln (x^{2} e^{x^{2 + 1}}))

Simplify

ln (x^{2} e^{x^{2 + 1}}) : ln (x^{2} e^{x^{3}})

= \frac{d}{d x} (ln (x^{2} e^{x^{3}}))

Apply the chain rule:

\frac{1}{x ^{2} e ^{x^{3}}} \frac{d}{d x} (x^{2} e^{x^{3}})

= \frac{1}{x ^{2} e ^{x^{3}}} \frac{d}{d x} (x^{2} e^{x^{3}})

\frac{d}{d x} (x^{2} e^{x^{3}}) = \frac{x e ^{x^{3}}}{∣ x ∣} + \frac{3 e ^{x^{3}} x ^{2} x ^{2}}{2 e ^{x^{3}}}

= \frac{1}{x ^{2} e ^{x^{3}}} (\frac{x e ^{x^{3}}}{∣ x ∣} + \frac{3 e ^{x^{3}} x ^{2} x ^{2}}{2 e ^{x^{3}}})

Simplify

\frac{1}{x ^{2} e ^{x^{3}}} (\frac{x e ^{x^{3}}}{∣ x ∣} + \frac{3 e ^{x^{3}} x ^{2} x ^{2}}{2 e ^{x^{3}}}) : \frac{3 x ^{2} ∣ x ∣ + 2}{2 ∣ x ∣}

= \frac{3 x ^{2} ∣ x ∣ + 2}{2 ∣ x ∣}

\int cot^{5} (x) csc^{2} (x) d x

\int_{2}^{5} t^{4} ln (2 t) d t

x \to 0 lim ((1 + \frac{4}{x ^{4}})^{x})

(\frac{- 9 x ^{2} + 12 x + 24}{( x ^{2} - 5 x - 6 ) ^{2}})^{^{'}}

\int \frac{( x ^{3} + 36 )}{x ^{2} + 36} d x

What is the derivative of ln(sqrt(x^2e^{x^{2+1)}}) ?
The derivative of ln(sqrt(x^2e^{x^{2+1)}}) is (3x^2|x|+2)/(2|x|)
What is the first derivative of ln(sqrt(x^2e^{x^{2+1)}}) ?
The first derivative of ln(sqrt(x^2e^{x^{2+1)}}) is (3x^2|x|+2)/(2|x|)