xy^'=y^2-y,y(2)=1

Lösung

x y^{^{'}} = y^{2} - y, y (2) = 1

y = 1

Schritte zur Lösung

x y^{'} (x) = y^{2} - y

Solve Bernoulli ODE:

y = 1

y = 1

\int_{0}^{1} \frac{1}{( x ^{2} + 1 ) ^{3}} d x

t an g e n t f (x) = 3 x^{2} - 5 x + 8, at x = 2

in v erse l a pl a ce \frac{2}{( s ^{2} - 1 ) ( s - 1 )}

\frac{\partial}{\partial y} (x^{2} + 5 y^{2})

x \to 3 - lim (- \frac{3}{7} x + \frac{4}{11})