ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

derivative y=t^2+5cos(t)

解

導関数

y = t^{2} + 5 cos (t)

解

2 t - 5 sin (t)

解答ステップ

\frac{d}{d t} (t^{2} + 5 cos (t))

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) + \frac{d}{d t} (5 cos (t))

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (5 cos (t)) = - 5 sin (t)

= 2 t - 5 sin (t)

グラフ

人気の例

(dy)/(dx)sin(x+y)=0

\frac{d y}{d x} sin (x + y) = 0

integral of (sec(x)+cos(x))/(4cos(x))

\int \frac{sec ( x ) + cos ( x )}{4 cos ( x )} d x

limit as x approaches 0 of x*log_{2}(x)

x \to 0 lim (x \cdot lo g_{2} (x))

面積 2x-1, 1/x ,x=3

a re a 2 x - 1, \frac{1}{x}, x = 3

derivative of 4x^3+x+5sin(x)

\frac{d}{d x} (4 x^{3} + x + 5 sin (x))