(\partial)/(\partial x)(sin(4x^2y-4xy^3))

Lösung

\frac{\partial}{\partial x} (sin (4 x^{2} y - 4 x y^{3}))

cos (4 x^{2} y - 4 x y^{3}) (8 y x - 4 y^{3})

Schritte zur Lösung

\frac{\partial}{\partial x} (sin (4 x^{2} y - 4 x y^{3}))

Behandle

y

als Konstante

Wende die Kettenregel an:

cos (4 x^{2} y - 4 x y^{3}) \frac{\partial}{\partial x} (4 x^{2} y - 4 x y^{3})

= cos (4 x^{2} y - 4 x y^{3}) \frac{\partial}{\partial x} (4 x^{2} y - 4 x y^{3})

\frac{\partial}{\partial x} (4 x^{2} y - 4 x y^{3}) = 8 y x - 4 y^{3}

= cos (4 x^{2} y - 4 x y^{3}) (8 y x - 4 y^{3})

d er i v a t i v e f (x) = \frac{6 x ^{2} + 8 x + 2}{x}

\int_{1}^{2} 5 x d x

\int_{0}^{π} cos^{2} (t) d t

d er i v a t i v e f (x) = x^{e^{x}}

d er i v a t i v e f (x) = 22 x