What is the tangent of f(x)= 6/(x^2),(1,6) ?

The tangent of f(x)= 6/(x^2),(1,6) is y=-12x+18

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tangent of f(x)= 6/(x^2),(1,6)

tangent of

f (x) = \frac{6}{x ^{2}}, (1, 6)

y = - 12 x + 18

Solution steps

Find the slope of

f (x) = \frac{6}{x ^{2}} : \frac{df ( x )}{d x} = - \frac{12}{x ^{3}}

Compute the slope of

f (x) = \frac{6}{x ^{2}}

(1, 6) : m = - 12

Find the line with slope m=

- 12

and passing through

(1, 6) : y = - 12 x + 18

y = - 12 x + 18

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6 + \frac{4}{x} + \frac{6}{x ^{2}}

\int 4^{x} (4^{x} + 1)^{3} d x

What is the tangent of f(x)= 6/(x^2),(1,6) ?
The tangent of f(x)= 6/(x^2),(1,6) is y=-12x+18