integral of (2-x)/(x^2-1)

Lösung

\int \frac{2 - x}{x ^{2} - 1} d x

- ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ - \frac{1}{2} ln x^{2} - 1 + C

Schritte zur Lösung

\int \frac{2 - x}{x ^{2} - 1} d x

Multipliziere aus

\frac{2 - x}{x ^{2} - 1} : \frac{2}{x ^{2} - 1} - \frac{x}{x ^{2} - 1}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x ^{2} - 1} d x - \int \frac{x}{x ^{2} - 1} d x

\int \frac{2}{x ^{2} - 1} d x = - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣

\int \frac{x}{x ^{2} - 1} d x = \frac{1}{2} ln x^{2} - 1

= - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ - \frac{1}{2} ln x^{2} - 1

Füge eine Konstante zur Lösung hinzu

= - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ - \frac{1}{2} ln x^{2} - 1 + C

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