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受欢迎的微积分 >

integral of 14tan^3(x)

解答

\int 14 tan^{3} (x) d x

解答

14 (- ln ∣ sec (x) ∣ + \frac{sec ^{2} ( x )}{2}) + C

求解步骤

\int 14 tan^{3} (x) d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 14 \cdot \int tan^{3} (x) d x

使用三角恒等式改写

= 14 \cdot \int (- 1 + sec^{2} (x)) tan (x) d x

使用换元积分法

= 14 \cdot \int \frac{- 1 + u ^{2}}{u} d u

乘开

\frac{- 1 + u ^{2}}{u} : - \frac{1}{u} + u

= 14 \cdot \int - \frac{1}{u} + u d u

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 14 (- \int \frac{1}{u} d u + \int u d u)

\int \frac{1}{u} d u = ln ∣ u ∣

\int u d u = \frac{u ^{2}}{2}

= 14 (- ln ∣ u ∣ + \frac{u ^{2}}{2})

u = sec (x)

代回

= 14 (- ln ∣ sec (x) ∣ + \frac{sec ^{2} ( x )}{2})

解答补常数

= 14 (- ln ∣ sec (x) ∣ + \frac{sec ^{2} ( x )}{2}) + C

作图

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y^{^{''}} - 2 y + y = 0

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\int_{- 4}^{6} f (x) d x

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x \to 0 lim (\frac{ln ( x )}{1})

y^{^{'}} - 9 x y = 0

derivative f(x)=3253(86.3)^x

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