derivative (1+x+x^2)^{99}

Lösung

ableitung von

(1 + x + x^{2})^{99}

99 (1 + x + x^{2})^{98} (2 x + 1)

Schritte zur Lösung

\frac{d}{d x} ((1 + x + x^{2})^{99})

Wende die Kettenregel an:

99 (1 + x + x^{2})^{98} \frac{d}{d x} (1 + x + x^{2})

= 99 (1 + x + x^{2})^{98} \frac{d}{d x} (1 + x + x^{2})

\frac{d}{d x} (1 + x + x^{2}) = 2 x + 1

= 99 (1 + x + x^{2})^{98} (2 x + 1)

\int e^{5 x^{2} + 10 x + 10} (x + 1) d x

\frac{d}{d x} (sin (\frac{x}{8}))

x \to 2 π - lim (e^{\frac{1}{x}} - x)

x \to - \frac{π}{2} lim (csc (\frac{x}{2}))

d er i v a t i v e ln (1 + 2 x)