derivative of sqrt(1+4sin(x))

Lösung

\frac{d}{d x} (1 + 4 sin (x))

\frac{2 cos ( x )}{1 + 4 sin ( x )}

Schritte zur Lösung

\frac{d}{d x} (1 + 4 sin (x))

Wende die Kettenregel an:

\frac{1}{2 1 + 4 sin ( x )} \frac{d}{d x} (1 + 4 sin (x))

= \frac{1}{2 1 + 4 sin ( x )} \frac{d}{d x} (1 + 4 sin (x))

\frac{d}{d x} (1 + 4 sin (x)) = 4 cos (x)

= \frac{1}{2 1 + 4 sin ( x )} \cdot 4 cos (x)

Vereinfache

\frac{1}{2 1 + 4 sin ( x )} \cdot 4 cos (x) : \frac{2 cos ( x )}{1 + 4 sin ( x )}

= \frac{2 cos ( x )}{1 + 4 sin ( x )}

\int - 2 y - y^{2} + 2 d y

t an g e n t f (x) = 1 - 7 x^{2}, (- 2, - 27)

\frac{\partial}{\partial x} (e^{x y} + \frac{x}{y})

y^{^{''}} + 13 y^{^{'}} + 42 y = 0

y^{^{''}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 0