1/4 y^{''}+4y=2tan(4t)

Lösung

\frac{1}{4} y^{^{''}} + 4 y = 2 tan (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{- 2 cos ( 4 t ) ( ln ( tan ( 4 t ) + sec ( 4 t ) ) - sin ( 4 t ) ) - sin ( 8 t )}{4}

Schritte zur Lösung

\frac{1}{4} y^{''} (t) + 4 y = 2 tan (4 t)

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{- 2 cos ( 4 t ) ( ln ( tan ( 4 t ) + sec ( 4 t ) ) - sin ( 4 t ) ) - sin ( 8 t )}{4}

y = c_{1} cos (4 t) + c_{2} sin (4 t) + \frac{- 2 cos ( 4 t ) ( ln ( tan ( 4 t ) + sec ( 4 t ) ) - sin ( 4 t ) ) - sin ( 8 t )}{4}

x \to 6 - lim (ln (x - 6))

d er i v a t i v e sin (1 + x^{2})

\frac{d}{d x} (sec^{3} (4 x))

l a pl a ce t r an s f or m cos (t + \frac{π}{5})

\int cos (4 t) - sin (4 t) d t