integral of 3cos(t)-2sin(t)

Lösung

\int 3 cos (t) - 2 sin (t) d t

3 sin (t) + 2 cos (t) + C

Schritte zur Lösung

\int 3 cos (t) - 2 sin (t) d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 cos (t) d t - \int 2 sin (t) d t

\int 3 cos (t) d t = 3 sin (t)

\int 2 sin (t) d t = - 2 cos (t)

= 3 sin (t) - (- 2 cos (t))

Vereinfache

= 3 sin (t) + 2 cos (t)

Füge eine Konstante zur Lösung hinzu

= 3 sin (t) + 2 cos (t) + C

l a pl a ce t r an s f or m e^{4 t} (t^{2} + 3 t + 5)

\int (- 9 x^{2} sec (3 x^{3} + 1)) d x

\frac{d}{d x} ((4 x)^{5 x})

\int (3 x)^{2} + 2 d x

x \to 1 lim (1 - 2 - x)