What is the integral of (cos(x)-3x^5) ?

The integral of (cos(x)-3x^5) is sin(x)-(x^6)/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (cos(x)-3x^5)

\int (cos (x) - 3 x^{5}) d x

sin (x) - \frac{x ^{6}}{2} + C

Solution steps

\int cos (x) - 3 x^{5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (x) d x - \int 3 x^{5} d x

\int cos (x) d x = sin (x)

\int 3 x^{5} d x = \frac{x ^{6}}{2}

= sin (x) - \frac{x ^{6}}{2}

Add a constant to the solution

= sin (x) - \frac{x ^{6}}{2} + C

\int 2 e^{x} - 3 d x

\int tanh (1 - 3 x) d x

\int \frac{x ^{2} + x}{x ( x - 1 ) ^{2}} d x

\int \frac{1}{3 x - 10} d x

\int 3 x e^{8 x^{2}} d x

What is the integral of (cos(x)-3x^5) ?
The integral of (cos(x)-3x^5) is sin(x)-(x^6)/2+C