integral from 1 to 2 of 3/(2x^3)

Lösung

\int_{1}^{2} \frac{3}{2 x ^{3}} d x

\frac{9}{16}

Dezimale

0.5625

Schritte zur Lösung

\int_{1}^{2} \frac{3}{2 x ^{3}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{2} \cdot \int_{1}^{2} \frac{1}{x ^{3}} d x

Wende die Potenzregel an

= \frac{3}{2} [- \frac{1}{2 x ^{2}}]_{1}^{2}

Berechne die Grenzen:

\frac{3}{8}

= \frac{3}{2} \cdot \frac{3}{8}

Vereinfache

= \frac{9}{16}

\int_{0}^{x^{2}} 3 sin (x) d x

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\int_{0}^{1} (x - x^{2})^{2} d x