integral from 0 to 1 of e^{x+e^x}

Lösung

\int_{0}^{1} e^{x + e^{x}} d x

e^{e} - e

Dezimale

12.43598 \dots

Schritte zur Lösung

\int_{0}^{1} e^{x + e^{x}} d x

Wende U-Substitution an

= \int_{1}^{e} e^{u} d u

Nutze das gemeinsame Integral :

\int e^{u} d u = e^{u}

= [e^{u}]_{1}^{e}

Berechne die Grenzen:

e^{e} - e

= e^{e} - e

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