integral from 0 to 4 of 3sqrt(x)

Lösung

\int_{0}^{4} 3 x d x

16

Schritte zur Lösung

\int_{0}^{4} 3 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{4} x d x

Wende die Potenzregel an

= 3 [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

Berechne die Grenzen:

\frac{16}{3}

= 3 \cdot \frac{16}{3}

Vereinfache

= 16

\int_{- 1}^{1} ∣ x ∣ - x^{2} d x

\int_{0}^{1} x 7 x^{2} + 9 d x

\int_{0}^{4} \frac{1}{4 t ^{2} + 9} d t

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\int_{0}^{1} sin^{2} (nπ x) d x