ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

integral from 0 to 2 of 6e^x

解

\int_{0}^{2} 6 e^{x} d x

解

6 (e^{2} - 1)

+1

十進法表記

38.33433 \dots

解答ステップ

\int_{0}^{2} 6 e^{x} d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{2} e^{x} d x

共通積分を使用する:

\int e^{x} d x = e^{x}

= 6 [e^{x}]_{0}^{2}

限度を計算する:

e^{2} - 1

= 6 (e^{2} - 1)

グラフ

人気の例

integral from 0 to 1 of x^{13}+13^x

\int_{0}^{1} x^{13} + 1 3^{x} d x

integral from 1 to 3 of (1/x)^2

\int_{1}^{3} (\frac{1}{x})^{2} d x

integral from 1 to 6 of 2x

\int_{1}^{6} 2 x d x

integral from 2 to 6 of x^2-7x+6

\int_{2}^{6} x^{2} - 7 x + 6 d x

integral from 5 to 8 of 10log_{4}(t)

\int_{5}^{8} 10 lo g_{4} (t) d t