integral from 0 to t^4 of sqrt(u)

Lösung

\int_{0}^{t^{4}} u d u

\frac{2 t ^{6}}{3}

Schritte zur Lösung

\int_{0}^{t^{4}} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{t^{4}}

Berechne die Grenzen:

\frac{2}{3} t^{6}

= \frac{2}{3} t^{6}

Vereinfache

= \frac{2 t ^{6}}{3}

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