integral from-1 to 1 of x-1

Lösung

\int_{- 1}^{1} x - 1 d x

- 2

Schritte zur Lösung

\int_{- 1}^{1} x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x d x - \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} x d x = 0

\int_{- 1}^{1} 1 d x = 2

= 0 - 2

Vereinfache

= - 2

\int_{0}^{1 - y} 1 d z

\int_{0}^{1} x (1 - x)^{9} d x

\int_{- x}^{x} x^{2} d x

\int_{1}^{2} 1 - 4 e^{- 3 x} d x

\int_{2}^{3} (x^{2} - 2 x + 1) d x