integral from 1 to 4 of |3x-6|

解答

\int_{1}^{4} ∣ 3 x - 6 ∣ d x

\frac{15}{2}

十进制

7.5

求解步骤

\int_{1}^{4} ∣ 3 x - 6 ∣ d x

拿掉绝对值

= \int_{1}^{2} - 3 x + 6 d x + \int_{2}^{4} 3 x - 6 d x

\int_{1}^{2} - 3 x + 6 d x = \frac{3}{2}

\int_{2}^{4} 3 x - 6 d x = 6

= \frac{3}{2} + 6

化简

\frac{3}{2} + 6 : \frac{15}{2}

= \frac{15}{2}

\int_{- 1}^{3} \frac{1}{x} d x

\int_{0}^{4} \frac{2}{2 x + 1} d x

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