integral from 0 to 1 of (x+3)^3

Lösung

\int_{0}^{1} (x + 3)^{3} d x

\frac{175}{4}

Dezimale

43.75

Schritte zur Lösung

\int_{0}^{1} (x + 3)^{3} d x

Wende U-Substitution an

= \int_{3}^{4} u^{3} d u

Wende die Potenzregel an

= [\frac{u ^{4}}{4}]_{3}^{4}

Berechne die Grenzen:

\frac{175}{4}

= \frac{175}{4}

\int_{- 1}^{3} \frac{1}{( y + 2 ) ^{3}} d y

\int_{3}^{4} 2^{- x} d x

\int_{0}^{l} (\frac{x}{l})^{2} d x

\int_{0}^{2} (- x^{2} - 3 x) d x

\int_{0}^{x} e^{\frac{- t ^{2}}{2}} d t