integral from 0 to 2pi of 8/3

解答

\int_{0}^{2 π} \frac{8}{3} d θ

\frac{16 π}{3}

十进制

16.75516 \dots

求解步骤

\int_{0}^{2 π} \frac{8}{3} d θ

常数积分:

\int a d x = a x

= [\frac{8}{3} θ]_{0}^{2 π}

带入上下限计算后得:

\frac{16 π}{3}

= \frac{16 π}{3}

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