integral from 2 to 1 of x^3

Lösung

\int_{2}^{1} x^{3} d x

- \frac{15}{4}

Dezimale

- 3.75

Schritte zur Lösung

\int_{2}^{1} x^{3} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{2} x^{3} d x

Wende die Potenzregel an

= - [\frac{x ^{4}}{4}]_{1}^{2}

Berechne die Grenzen:

\frac{15}{4}

= - \frac{15}{4}

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