integral from 0 to 2 of 2x+2

Lösung

\int_{0}^{2} 2 x + 2 d x

8

Schritte zur Lösung

\int_{0}^{2} 2 x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 2 x d x + \int_{0}^{2} 2 d x

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 2 d x = 4

= 4 + 4

Vereinfache

= 8

\int_{0}^{5} ∣ 3 t - 8 ∣ d t

\int_{1}^{5} - \frac{1}{5} x + 1 d x

\int_{0}^{3} \frac{1}{16 + x ^{2}} d x

\int_{- 2}^{2} t^{2} d t

\int_{- 1}^{1} (x + x^{3}) d x