integral from 50 to 100 of x/(24+5x^2)

Lösung

\int_{50}^{100} \frac{x}{24 + 5 x ^{2}} d x

\frac{1}{10} ln (\frac{12506}{3131})

Dezimale

0.13848 \dots

Schritte zur Lösung

\int_{50}^{100} \frac{x}{24 + 5 x ^{2}} d x

Wende U-Substitution an

= \int_{12524}^{50024} \frac{1}{10 u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{10} \cdot \int_{12524}^{50024} \frac{1}{u} d u

Nutze das gemeinsame Integral :

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{10} [ln ∣ u ∣]_{12524}^{50024}

Berechne die Grenzen:

ln (50024) - ln (12524)

= \frac{1}{10} (ln (50024) - ln (12524))

Vereinfache

= \frac{1}{10} ln (\frac{12506}{3131})

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