integral from 0 to 2 of (8x-x^4)

Lösung

\int_{0}^{2} (8 x - x^{4}) d x

\frac{48}{5}

Dezimale

9.6

Schritte zur Lösung

\int_{0}^{2} 8 x - x^{4} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 8 x d x - \int_{0}^{2} x^{4} d x

\int_{0}^{2} 8 x d x = 16

\int_{0}^{2} x^{4} d x = \frac{32}{5}

= 16 - \frac{32}{5}

Vereinfache

16 - \frac{32}{5} : \frac{48}{5}

= \frac{48}{5}

\int_{2}^{6} (x^{3} - 4 x) d x

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