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人気のある微分積分 >

integral from 1 to 2 of 1/((3-x)^2)

解

\int_{1}^{2} \frac{1}{( 3 - x ) ^{2}} d x

解

\frac{1}{2}

+1

十進法表記

0.5

解答ステップ

\int_{1}^{2} \frac{1}{( 3 - x ) ^{2}} d x

u置換積分法を適用する

= \int_{2}^{1} - \frac{1}{u ^{2}} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{2} - \frac{1}{u ^{2}} d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{1}^{2} \frac{1}{u ^{2}} d u)

べき乗則を適用する

= - (- [- \frac{1}{u}]_{1}^{2})

簡素化

= [- \frac{1}{u}]_{1}^{2}

限度を計算する:

\frac{1}{2}

= \frac{1}{2}

グラフ

人気の例

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