integral from-1 to 1 of (x^2+x^4sin(x))

Lösung

\int_{- 1}^{1} (x^{2} + x^{4} sin (x)) d x

\frac{2}{3}

Dezimale

0.66666 \dots

Schritte zur Lösung

\int_{- 1}^{1} x^{2} + x^{4} sin (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x + \int_{- 1}^{1} x^{4} sin (x) d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} x^{4} sin (x) d x = 0

= \frac{2}{3} + 0

Vereinfache

= \frac{2}{3}

\int_{1}^{2} (4 x^{3} + \frac{6}{x ^{2}}) d x

\int_{- 3}^{3} e^{u + 3} d u

\int_{0}^{2} e^{x} x d x

\int_{0}^{2} 4 + x^{2}^{3} d x

\int_{0}^{5} 6 e^{3 x} d x