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人気のある微分積分 >

integral from 9 to x^3 of 1/(p^2)

解

\int_{9}^{x^{3}} \frac{1}{p ^{2}} d p

解

- \frac{1}{x ^{3}} + \frac{1}{9}

解答ステップ

\int_{9}^{x^{3}} \frac{1}{p ^{2}} d p

べき乗則を適用する

= [- \frac{1}{p}]_{9}^{x^{3}}

限度を計算する:

- \frac{1}{x ^{3}} + \frac{1}{9}

= - \frac{1}{x ^{3}} + \frac{1}{9}

人気の例

integral from 0 to 4 of t^3

\int_{0}^{4} t^{3} d t

integral from-2 to 4 of (y+4)/2-(y^2)/4

\int_{- 2}^{4} \frac{y + 4}{2} - \frac{y ^{2}}{4} d y

integral from 0 to cos(θ) of cos(y)

\int_{0}^{c o s (θ)} cos (y) d y

integral from 0 to 10 of 10e^{0.02x}

\int_{0}^{10} 10 e^{0.02 x} d x

integral from 1 to 2 of 5x^4

\int_{1}^{2} 5 x^{4} d x