integral from 1 to 4 of 2x-3

Lösung

\int_{1}^{4} 2 x - 3 d x

6

Schritte zur Lösung

\int_{1}^{4} 2 x - 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 2 x d x - \int_{1}^{4} 3 d x

\int_{1}^{4} 2 x d x = 15

\int_{1}^{4} 3 d x = 9

= 15 - 9

Vereinfache

= 6

\int_{2}^{6} 4 x d x

\int_{0}^{0} ln (z + 2) d z

\int_{0}^{\frac{1}{2}} (sin (π x)) d x

\int_{0}^{2 π} - 36 sin^{2} (t) d t

\int_{0}^{2} 36 t^{2} + 9 t^{4} d t