integral from 0 to 3 of x^2-6x+9

Lösung

\int_{0}^{3} x^{2} - 6 x + 9 d x

9

Schritte zur Lösung

\int_{0}^{3} x^{2} - 6 x + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{2} d x - \int_{0}^{3} 6 x d x + \int_{0}^{3} 9 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 6 x d x = 27

\int_{0}^{3} 9 d x = 27

= 9 - 27 + 27

Vereinfache

= 9

\int_{0}^{1} 6 e^{3 x} d x

\int_{0}^{4} 6 - 2 x d x

\int_{- 2}^{5} (3 + x - 2 ∣ x ∣) d x

\int_{1}^{2} 8 x d x

\int_{0}^{3} (6 + 6 y - y^{2}) d y