integral from 0 to x of (4-x^2)

Lösung

\int_{0}^{x} (4 - x^{2}) d x

4 x - \frac{x ^{3}}{3}

Schritte zur Lösung

\int_{0}^{x} 4 - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{x} 4 d x - \int_{0}^{x} x^{2} d x

\int_{0}^{x} 4 d x = 4 x

\int_{0}^{x} x^{2} d x = \frac{x ^{3}}{3}

= 4 x - \frac{x ^{3}}{3}

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