integral from 1 to 2 of-1/2 x+4

Lösung

\int_{1}^{2} - \frac{1}{2} x + 4 d x

\frac{13}{4}

Dezimale

3.25

Schritte zur Lösung

\int_{1}^{2} - \frac{1}{2} x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{2} \frac{1}{2} x d x + \int_{1}^{2} 4 d x

\int_{1}^{2} \frac{1}{2} x d x = \frac{3}{4}

\int_{1}^{2} 4 d x = 4

= - \frac{3}{4} + 4

Vereinfache

- \frac{3}{4} + 4 : \frac{13}{4}

= \frac{13}{4}

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