integral from 0 to 3 of 2t-3

Lösung

\int_{0}^{3} 2 t - 3 d t

0

Schritte zur Lösung

\int_{0}^{3} 2 t - 3 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 2 t d t - \int_{0}^{3} 3 d t

\int_{0}^{3} 2 t d t = 9

\int_{0}^{3} 3 d t = 9

= 9 - 9

Vereinfache

= 0

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