integral from 1 to 2 of 1/x+x

Lösung

\int_{1}^{2} \frac{1}{x} + x d x

ln (2) + \frac{3}{2}

Dezimale

2.19314 \dots

Schritte zur Lösung

\int_{1}^{2} \frac{1}{x} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{1}{x} d x + \int_{1}^{2} x d x

\int_{1}^{2} \frac{1}{x} d x = ln (2)

\int_{1}^{2} x d x = \frac{3}{2}

= ln (2) + \frac{3}{2}

\int_{0}^{\frac{π}{2}} \frac{1 + cos ( 2 x )}{2} d x

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