ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

integral from 0 to 1 of (2+\sqrt[3]{x})

解

\int_{0}^{1} (2 + 3 x) d x

解

\frac{11}{4}

+1

十進法表記

2.75

解答ステップ

\int_{0}^{1} 2 + 3 x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 d x + \int_{0}^{1} 3 x d x

\int_{0}^{1} 2 d x = 2

\int_{0}^{1} 3 x d x = \frac{3}{4}

= 2 + \frac{3}{4}

簡素化

2 + \frac{3}{4} : \frac{11}{4}

= \frac{11}{4}

グラフ

人気の例

integral from 0 to 1 of sin(u)

\int_{0}^{1} sin (u) d u

integral from 0 to 3 of 24-8x

\int_{0}^{3} 24 - 8 x d x

integral from 0 to 3 of 1/5 e^{-x/5}

\int_{0}^{3} \frac{1}{5} e^{- \frac{x}{5}} d x

integral from 0 to 4 of (2t-1)^2

\int_{0}^{4} (2 t - 1)^{2} d t

integral from-6 to 0 of (4+sqrt(36-x^2))

\int_{- 6}^{0} (4 + 36 - x^{2}) d x