integral from 0 to 1 of (2+\sqrt[3]{x})

Lösung

\int_{0}^{1} (2 + 3 x) d x

\frac{11}{4}

Dezimale

2.75

Schritte zur Lösung

\int_{0}^{1} 2 + 3 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 d x + \int_{0}^{1} 3 x d x

\int_{0}^{1} 2 d x = 2

\int_{0}^{1} 3 x d x = \frac{3}{4}

= 2 + \frac{3}{4}

Vereinfache

2 + \frac{3}{4} : \frac{11}{4}

= \frac{11}{4}

\int_{0}^{1} sin (u) d u

\int_{0}^{3} 24 - 8 x d x

\int_{0}^{3} \frac{1}{5} e^{- \frac{x}{5}} d x

\int_{0}^{4} (2 t - 1)^{2} d t

\int_{- 6}^{0} (4 + 36 - x^{2}) d x