integral from 0 to 2 of e^x-1

Lösung

\int_{0}^{2} e^{x} - 1 d x

e^{2} - 3

Dezimale

4.38905 \dots

Schritte zur Lösung

\int_{0}^{2} e^{x} - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} e^{x} d x - \int_{0}^{2} 1 d x

\int_{0}^{2} e^{x} d x = e^{2} - 1

\int_{0}^{2} 1 d x = 2

= e^{2} - 1 - 2

Vereinfache

= e^{2} - 3

\int_{5}^{7} x^{2} + 2 x - 16 d x

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