integral from 0 to 5 of 2.5x

Lösung

\int_{0}^{5} 2.5 x d x

31.25

Schritte zur Lösung

\int_{0}^{5} 2.5 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2.5 \cdot \int_{0}^{5} x d x

Wende die Potenzregel an

= 2.5 [\frac{x ^{2}}{2}]_{0}^{5}

Vereinfache

= 2.5 [0.5 x^{2}]_{0}^{5}

Berechne die Grenzen:

12.5

= 2.5 \cdot 12.5

Vereinfache

= 31.25

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