integral from 0 to 1 of 3x(x^2-1)^{12}

Lösung

\int_{0}^{1} 3 x (x^{2} - 1)^{12} d x

\frac{3}{26}

Dezimale

0.11538 \dots

Schritte zur Lösung

\int_{0}^{1} 3 x (x^{2} - 1)^{12} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} x (x^{2} - 1)^{12} d x

Wende U-Substitution an

= 3 \cdot \int_{- 1}^{0} \frac{u ^{12}}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{2} \cdot \int_{- 1}^{0} u^{12} d u

Wende die Potenzregel an

= 3 \cdot \frac{1}{2} [\frac{u ^{13}}{13}]_{- 1}^{0}

Vereinfache

3 \cdot \frac{1}{2} [\frac{u ^{13}}{13}]_{- 1}^{0} : \frac{3}{2} [\frac{u ^{13}}{13}]_{- 1}^{0}

= \frac{3}{2} [\frac{u ^{13}}{13}]_{- 1}^{0}

Berechne die Grenzen:

\frac{1}{13}

= \frac{3}{2} \cdot \frac{1}{13}

Vereinfache

= \frac{3}{26}

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