integral from 0 to 2pi of 64

Lösung

\int_{0}^{2 π} 64 d x

128 π

Dezimale

402.12385 \dots

Schritte zur Lösung

\int_{0}^{2 π} 64 d x

Integral einer Konstanten :

\int a d x = a x

= [64 x]_{0}^{2 π}

Berechne die Grenzen:

128 π

= 128 π

\int_{1}^{5} x^{3} + \frac{1}{x ^{3}} d x

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\int_{0}^{2} (2 x^{2} - x^{3}) d x