integral of 1/48 x

解答

\int \frac{1}{48} x d x

\frac{x ^{2}}{96} + C

求解步骤

\int \frac{1}{48} x d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{48} \cdot \int x d x

使用幂法则

= \frac{1}{48} \cdot \frac{x ^{2}}{2}

化简

\frac{1}{48} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{96}

= \frac{x ^{2}}{96}

解答补常数

= \frac{x ^{2}}{96} + C

d er i v a t i v e \frac{10 x + 8 x ^{2}}{( 5 + 8 x ) ^{2}}

\int (6 x^{2}) (2 x^{3} + 1)^{2} d x

d er i v a t i v e 2 sec (θ)

d er i v a t i v e f (x) = tan (2 x)

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