limit as x approaches-1 of 1/(x^2+1)

解答

x \to - 1 lim (\frac{1}{x ^{2} + 1})

\frac{1}{2}

十进制

0.5

求解步骤

x \to - 1 lim (\frac{1}{x ^{2} + 1})

代入值

x = - 1

= \frac{1}{( - 1 ) ^{2} + 1}

(- 1)^{2} + 1 = 2

= \frac{1}{2}

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